Statistiques concernant Révisions : Mathématiques

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Statistiques générales

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  • Le résultat moyen est 25 sur 140

Statistiques - réponses

QuestionsRéponses% Correct
sin(x) ∼x
67%
x^(1/2)1/(2x^(1/2))
56%
1/x-1/x^2
56%
cos(-x) =cos(x)
56%
sin(-x) =-sin(x)
56%
1/x^2-1/x
44%
exp(x) =1+x+(x^2/2!)+(x^3/3!)+○(x^3)
44%
cos(a+b) =cos(a)cos(b)-sin(a)sin(b)
44%
cos(a-b) =cos(a)cos(b)+sin(a)sin(b)
44%
sin(π/2+x) =cos(x)
44%
cos(π-x) =-cos(x)
44%
x^nnx^n-1
44%
sin(π-x) =sin(x)
44%
cos(π/2-x) =sin(x)
44%
tan(x) ∼x
44%
1-cos(x) ∼x^2/2
44%
x^nx^(n+1)/(n+1)
44%
lim sin(x)/x =1
33%
lim exp(x)-1/x =1
33%
lim ln(1+x)/x =1
33%
lim 1-cos(x)/x^2 =1/2
33%
exp(-a) =1/exp(a)
33%
cos(x) =1-(x^2/2!)+○(x^3)
33%
1/(1+x) =1-x+x^2-x^3+○(x^3)
33%
1/(1-x) =1+x+x^2+x^3+○(x^3)
33%
1/x^(1/2)2(x^(1/2))
33%
͞z =a-ib
33%
cos(π+x) =-cos(x)
33%
sin(x)cos(x)
33%
exp(a)exp(b) =exp(a+b)
33%
exp(a)/exp(b) =exp(a-b)
33%
ln(1/a) =-ln(a)
33%
ln(a/b) =ln(a)-ln(b)
33%
ln(ab) =ln(a)+ln(b)
33%
ln(a^n) =nln(a)
33%
sin(π+x) =-sin(x)
33%
cos(x)-sin(x)
33%
tan(π+x) =tan(x)
33%
tan(-x) =-tan(x)
33%
ln(1+x) ∼x
33%
exp(x) ∼x
33%
ln(1+x) =x-(x^2/2)+(x^3/3)+○(x^3)
33%
sin (x) =x-(x^3/3!)+○(x^3)
33%
a0(f) =1/T∫f(t)dt
22%
ln(x)1/x
22%
ch(x) =1+(x^2/2!)+○(x^3)
22%
ax+by+c=0
22%
exp(iϴ) =cos(ϴ)+isin(ϴ)
22%
sin(x)-cos(x)
22%
exp(a)^n =exp(na)
22%
exp(x)exp(x)
22%
Σ k =n(n+1)/2
22%
cos(x)sin(x)
22%
sh(x) =x+(x^^3/3!)+○(x^3)
22%
u·v =0
11%
bn(f) =0
11%
an(f) =0
11%
a0(f) =0
11%
det(u;v) =0
11%
det(u,u) =0
11%
(n;0) =1
11%
th(x)1/ch^2(x)
11%
tan(x)1/cos^2(x)
11%
Σ q^k =1-q^(n+1)/1-q
11%
1-sin^2(a)
11%
tan(x)1+tan^2(x)
11%
th(x)1-th^2(x)
11%
an(f) =2/T∫f(t)cos(nωt)dt
11%
a0(f) =2/T∫f(t)dt
11%
bn(f) =2/T∫f(t)sin(nωt)dt
11%
an(f) =4/T∫f(t)cos(nωt)dt
11%
bn(f) =4/T∫f(t)sin(nωt)dt
11%
͞zz =a^2+b^2
11%
|z| =(a^2+b^2)^(1/2)
11%
ax+by+cz+d=0
11%
sh(x)ch(x)
11%
cos(2a) =cos^2(a)-sin^2(a)
11%
(cos(ϴ)+isin(ϴ))^n =cos(nϴ)+isin(nϴ)
11%
det(v,u) =-det(u,v)
11%
det(λu+μv,w) =λdet(u,w)+μdet(v,w)
11%
cos(ϴ) =(exp(iϴ)+exp(-iϴ))/2
11%
sin(ϴ) =(exp(iϴ)-exp(-iϴ))/2i
11%
ch(x) =(exp(x)+exp(-x))/2
11%
sh(x) =(exp(x)-exp(-x))/2
11%
Si f(-x) = -f(x) alors f estimpaire
11%
1/xln(x)
11%
(n;1) =n
11%
Σ q^k =n+1
11%
(n;p)+(n;p+1) =(n+1;p+1)
11%
Si f(-x) = f(x) alors f estpaire
11%
z+͞z/2 =Re(z)
11%
ch(x)sh(x)
11%
th(x) =sh(x)/ch(x)
11%
sin(a+b) =sin(a)cos(b)+sin(b)cos(a)
11%
sin(a-b) =sin(a)cos(b)-sin(b)cos(a)
11%
tan(a-b) =(tan(a)-tan(b))/1+tan(a)tan(b)
11%
tan(a+b) =(tan(a)+tan(b))/1-tan(a)tan(b)
11%
[u,v,w] =(u∧v)·w
11%
(1+x)^α ∼αx
11%
(x-xΩ)^2+(y-yΩ)^2=R^2
11%
tan(x) =x+(x^3/3)+○(x^3)
11%
x=xa+αt
11%
u·v =xx'+yy'
11%
det(u,v) =xy'+x'y
11%
y=ya+βt
11%
arctan(x)1/(1+x^2)
0%
arcsin(x)1/(1-x^2)^(1/2)
0%
arccos(x)-1/(1-x^2)^(1/2)
0%
(1+x)^α =1+αx+((α(α-1)x^2)/2!)+((α(α-1)(α-2)x^3/3!)○(x^3)
0%
2cos^2(a)-1
0%
sin(2a) =2sin(a)cos(a)
0%
tan(2a) =2tan(a)/(1-tan²(a))
0%
1/(1-x^2)^(1/2)arcsin(x)
0%
1/(1+x^2)arctan(x)
0%
ax+by+cz+d=0
0%
a'x+b'y+c'z+d'=0
0%
sh(x)ch(x)
0%
λexp(r1x)+μexp(r2x)
0%
λexp(r1x)+μexp(r2x)
0%
exp(x)exp(x)
0%
exp(αx)(λcos(βx)+μsin(βx))
0%
th(x)ln|ch(x)|
0%
tan(x)-ln|cos(x)|
0%
(n;0) =(n;n)
0%
(n;1) =(n;n-1)
0%
(n;p) =(n;n-p)
0%
ch(x)sh(x)
0%
1+tan^2(x)tan(x)
0%
1/cos^2(x)tan(x)
0%
1-th²(x)th(x)
0%
1/ch²(x)th(x)
0%
(λx+μ)exp(r0x)
0%
(λx+μ)exp(r0x)
0%
(x-xΩ)^2+(y-yΩ)^2+(z-zΩ)^2=R^2
0%
x=xa+αt
0%
x=xa+αt+α's
0%
y=ya+βt
0%
y=ya+βt+β's
0%
z=za+γt
0%
z=za+γt+γ's
0%

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